114013231034443 has 4 divisors (see below), whose sum is σ = 122783479575568. Its totient is φ = 105242982493320.

The previous prime is 114013231034419. The next prime is 114013231034471. The reversal of 114013231034443 is 344430132310411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114013231034443 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114013231034399 and 114013231034408.

It is not an unprimeable number, because it can be changed into a prime (114013231034473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4385124270543 + ... + 4385124270568.

It is an arithmetic number, because the mean of its divisors is an integer number (30695869893892).

Almost surely, 2^{114013231034443} is an apocalyptic number.

114013231034443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

114013231034443 is a deficient number, since it is larger than the sum of its proper divisors (8770248541125).

114013231034443 is an equidigital number, since it uses as much as digits as its factorization.

114013231034443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8770248541124.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 114013231034443 its reverse (344430132310411), we get a palindrome (458443363344854).

The spelling of 114013231034443 in words is "one hundred fourteen trillion, thirteen billion, two hundred thirty-one million, thirty-four thousand, four hundred forty-three".