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114013303 = 152374861
BaseRepresentation
bin1101100101110…
…11010001110111
321221112110211221
412302323101313
5213141411203
615151411211
72553045205
oct662732167
9257473757
10114013303
11593a2978
1232223b07
131a80bcc1
14111dc075
15a021abd
hex6cbb477

114013303 has 4 divisors (see below), whose sum is σ = 114089688. Its totient is φ = 113936920.

The previous prime is 114013301. The next prime is 114013309. The reversal of 114013303 is 303310411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114013303 - 21 = 114013301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114013301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35908 + ... + 38953.

It is an arithmetic number, because the mean of its divisors is an integer number (28522422).

Almost surely, 2114013303 is an apocalyptic number.

114013303 is a deficient number, since it is larger than the sum of its proper divisors (76385).

114013303 is an equidigital number, since it uses as much as digits as its factorization.

114013303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76384.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 114013303 is about 10677.7012039109. The cubic root of 114013303 is about 484.8996185777.

Adding to 114013303 its reverse (303310411), we get a palindrome (417323714).

The spelling of 114013303 in words is "one hundred fourteen million, thirteen thousand, three hundred three".

Divisors: 1 1523 74861 114013303