Base | Representation |
---|---|
bin | 110101000101110111… |
… | …0101100001101100001 |
3 | 101220021210100221221101 |
4 | 1222023232230031201 |
5 | 3331444414004213 |
6 | 124213235154401 |
7 | 11144234046331 |
oct | 1521356541541 |
9 | 356253327841 |
10 | 114013422433 |
11 | 44397671859 |
12 | 1a11aa45a01 |
13 | a99cb3ab91 |
14 | 573822d0c1 |
15 | 2e7461ebdd |
hex | 1a8bbac361 |
114013422433 has 8 divisors (see below), whose sum is σ = 114326614656. Its totient is φ = 113700560400.
The previous prime is 114013422407. The next prime is 114013422449. The reversal of 114013422433 is 334224310411.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114013422433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114013422473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 617103 + ... + 780283.
It is an arithmetic number, because the mean of its divisors is an integer number (14290826832).
Almost surely, 2114013422433 is an apocalyptic number.
It is an amenable number.
114013422433 is a deficient number, since it is larger than the sum of its proper divisors (313192223).
114013422433 is a wasteful number, since it uses less digits than its factorization.
114013422433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 165095.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 114013422433 its reverse (334224310411), we get a palindrome (448237732844).
The spelling of 114013422433 in words is "one hundred fourteen billion, thirteen million, four hundred twenty-two thousand, four hundred thirty-three".
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