114013534114131 has 16 divisors (see below), whose sum is σ = 152203398332160. Its totient is φ = 75916348705440.

The previous prime is 114013534114099. The next prime is 114013534114133. The reversal of 114013534114131 is 131411435310411.

It is not a de Polignac number, because 114013534114131 - 2⁵ = 114013534114099 is a prime.

It is a super-2 number, since 2×114013534114131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114013534114092 and 114013534114101.

It is not an unprimeable number, because it can be changed into a prime (114013534114133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 225574626 + ... + 226079496.

It is an arithmetic number, because the mean of its divisors is an integer number (9512712395760).

Almost surely, 2^{114013534114131} is an apocalyptic number.

114013534114131 is a deficient number, since it is larger than the sum of its proper divisors (38189864218029).

114013534114131 is an equidigital number, since it uses as much as digits as its factorization.

114013534114131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 596506.

The product of its (nonzero) digits is 8640, while the sum is 33.

Adding to 114013534114131 its reverse (131411435310411), we get a palindrome (245424969424542).

The spelling of 114013534114131 in words is "one hundred fourteen trillion, thirteen billion, five hundred thirty-four million, one hundred fourteen thousand, one hundred thirty-one".