Base | Representation |
---|---|
bin | 11001111011000111011000… |
… | …111000101100010011100101 |
3 | 112221200120220000200220011201 |
4 | 121323013120320230103211 |
5 | 104420444220134100032 |
6 | 1042253033315202501 |
7 | 33005130642366445 |
oct | 3173073070542345 |
9 | 487616800626151 |
10 | 114013545612517 |
11 | 33367967197a51 |
12 | 109547098a6431 |
13 | 4b8057b504015 |
14 | 20223dc276125 |
15 | d2ab499978e7 |
hex | 67b1d8e2c4e5 |
114013545612517 has 4 divisors (see below), whose sum is σ = 114013612987456. Its totient is φ = 114013478237580.
The previous prime is 114013545612503. The next prime is 114013545612523. The reversal of 114013545612517 is 715216545310411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114013545612517 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114013545612017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31081959 + ... + 34555972.
It is an arithmetic number, because the mean of its divisors is an integer number (28503403246864).
Almost surely, 2114013545612517 is an apocalyptic number.
It is an amenable number.
114013545612517 is a deficient number, since it is larger than the sum of its proper divisors (67374939).
114013545612517 is an equidigital number, since it uses as much as digits as its factorization.
114013545612517 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67374938.
The product of its (nonzero) digits is 504000, while the sum is 46.
The spelling of 114013545612517 in words is "one hundred fourteen trillion, thirteen billion, five hundred forty-five million, six hundred twelve thousand, five hundred seventeen".
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