11401413311 has 4 divisors (see below), whose sum is σ = 11404546632. Its totient is φ = 11398279992.

The previous prime is 11401413293. The next prime is 11401413427. The reversal of 11401413311 is 11331410411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11331410411 = 83 ⋅136523017.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11401413311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11401418311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1561196 + ... + 1568481.

It is an arithmetic number, because the mean of its divisors is an integer number (2851136658).

Almost surely, 2^11401413311 is an apocalyptic number.

11401413311 is a deficient number, since it is larger than the sum of its proper divisors (3133321).

11401413311 is an equidigital number, since it uses as much as digits as its factorization.

11401413311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3133320.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11401413311 its reverse (11331410411), we get a palindrome (22732823722).

The spelling of 11401413311 in words is "eleven billion, four hundred one million, four hundred thirteen thousand, three hundred eleven".