Base | Representation |
---|---|
bin | 110101000101111000… |
… | …1110010001000100011 |
3 | 101220021211220010222221 |
4 | 1222023301302020203 |
5 | 3332000120424443 |
6 | 124213304411511 |
7 | 11144243664010 |
oct | 1521361621043 |
9 | 356254803887 |
10 | 114014233123 |
11 | 4439807594a |
12 | 1a11b176b97 |
13 | a9a0062b8b |
14 | 57383a0707 |
15 | 2e7472eeed |
hex | 1a8bc72223 |
114014233123 has 4 divisors (see below), whose sum is σ = 130301980720. Its totient is φ = 97726485528.
The previous prime is 114014233121. The next prime is 114014233141. The reversal of 114014233123 is 321332410411.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 321332410411 = 349 ⋅920723239.
It is not a de Polignac number, because 114014233123 - 21 = 114014233121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114014233121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8143873788 + ... + 8143873801.
It is an arithmetic number, because the mean of its divisors is an integer number (32575495180).
Almost surely, 2114014233123 is an apocalyptic number.
114014233123 is a deficient number, since it is larger than the sum of its proper divisors (16287747597).
114014233123 is an equidigital number, since it uses as much as digits as its factorization.
114014233123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16287747596.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 114014233123 its reverse (321332410411), we get a palindrome (435346643534).
The spelling of 114014233123 in words is "one hundred fourteen billion, fourteen million, two hundred thirty-three thousand, one hundred twenty-three".
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