11401441133 has 4 divisors (see below), whose sum is σ = 11411347968. Its totient is φ = 11391534300.

The previous prime is 11401441097. The next prime is 11401441189. The reversal of 11401441133 is 33114410411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33114410411 = 54949 ⋅602639.

It is a cyclic number.

It is not a de Polignac number, because 11401441133 - 2⁶ = 11401441069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11401441099 and 11401441108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11401441433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4951691 + ... + 4953992.

It is an arithmetic number, because the mean of its divisors is an integer number (2852836992).

Almost surely, 2^11401441133 is an apocalyptic number.

It is an amenable number.

11401441133 is a deficient number, since it is larger than the sum of its proper divisors (9906835).

11401441133 is an equidigital number, since it uses as much as digits as its factorization.

11401441133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9906834.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11401441133 its reverse (33114410411), we get a palindrome (44515851544).

The spelling of 11401441133 in words is "eleven billion, four hundred one million, four hundred forty-one thousand, one hundred thirty-three".