Base | Representation |
---|---|
bin | 11001111011001101100000… |
… | …010101110100110100111011 |
3 | 112221201012211201122220122021 |
4 | 121323031200111310310323 |
5 | 104421101142431003201 |
6 | 1042300041124135311 |
7 | 33005452460433115 |
oct | 3173154025646473 |
9 | 487635751586567 |
10 | 114020113141051 |
11 | 3336a727408387 |
12 | 10955a41237537 |
13 | 4b81087039790 |
14 | 20228625b83b5 |
15 | d2add1336ea1 |
hex | 67b360574d3b |
114020113141051 has 4 divisors (see below), whose sum is σ = 122790891074992. Its totient is φ = 105249335207112.
The previous prime is 114020113141001. The next prime is 114020113141061. The reversal of 114020113141051 is 150141311020411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114020113141051 - 211 = 114020113139003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114020113141001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4385388966951 + ... + 4385388966976.
It is an arithmetic number, because the mean of its divisors is an integer number (30697722768748).
Almost surely, 2114020113141051 is an apocalyptic number.
114020113141051 is a deficient number, since it is larger than the sum of its proper divisors (8770777933941).
114020113141051 is an equidigital number, since it uses as much as digits as its factorization.
114020113141051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8770777933940.
The product of its (nonzero) digits is 480, while the sum is 25.
Adding to 114020113141051 its reverse (150141311020411), we get a palindrome (264161424161462).
The spelling of 114020113141051 in words is "one hundred fourteen trillion, twenty billion, one hundred thirteen million, one hundred forty-one thousand, fifty-one".
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