Base | Representation |
---|---|
bin | 110101000110000110… |
… | …0011100100001100111 |
3 | 101220022100001020121212 |
4 | 1222030030130201213 |
5 | 3332003413110003 |
6 | 124214114302035 |
7 | 11144360254136 |
oct | 1521414344147 |
9 | 356270036555 |
10 | 114021222503 |
11 | 443a100a0a1 |
12 | 1a12158791b |
13 | a9a163c2c6 |
14 | 573929d91d |
15 | 2e75160dd8 |
hex | 1a8c31c867 |
114021222503 has 4 divisors (see below), whose sum is σ = 114680304888. Its totient is φ = 113362140120.
The previous prime is 114021222473. The next prime is 114021222521. The reversal of 114021222503 is 305222120411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114021222503 - 214 = 114021206119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114021222533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 329540933 + ... + 329541278.
It is an arithmetic number, because the mean of its divisors is an integer number (28670076222).
Almost surely, 2114021222503 is an apocalyptic number.
114021222503 is a deficient number, since it is larger than the sum of its proper divisors (659082385).
114021222503 is an equidigital number, since it uses as much as digits as its factorization.
114021222503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 659082384.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 114021222503 its reverse (305222120411), we get a palindrome (419243342914).
The spelling of 114021222503 in words is "one hundred fourteen billion, twenty-one million, two hundred twenty-two thousand, five hundred three".
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