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114022013 = 716288859
BaseRepresentation
bin1101100101111…
…01011001111101
321221112220210112
412302331121331
5213142201023
615151515405
72553112460
oct662753175
9257486715
10114022013
11593a9476
1232228b65
131a812c61
14112012d7
15a024478
hex6cbd67d

114022013 has 4 divisors (see below), whose sum is σ = 130310880. Its totient is φ = 97733148.

The previous prime is 114022003. The next prime is 114022019. The reversal of 114022013 is 310220411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 310220411 = 941329671.

It is a cyclic number.

It is not a de Polignac number, because 114022013 - 28 = 114021757 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114022019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8144423 + ... + 8144436.

It is an arithmetic number, because the mean of its divisors is an integer number (32577720).

Almost surely, 2114022013 is an apocalyptic number.

It is an amenable number.

114022013 is a deficient number, since it is larger than the sum of its proper divisors (16288867).

114022013 is an equidigital number, since it uses as much as digits as its factorization.

114022013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16288866.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 114022013 is about 10678.1090554461. The cubic root of 114022013 is about 484.9119661664.

Adding to 114022013 its reverse (310220411), we get a palindrome (424242424).

The spelling of 114022013 in words is "one hundred fourteen million, twenty-two thousand, thirteen".

Divisors: 1 7 16288859 114022013