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1140233214413 = 1394838174711
BaseRepresentation
bin10000100101111011001…
…100100001100111001101
311001000010210221211021002
4100211323030201213031
5122140144200330123
62231452122550045
7145244020256516
oct20457314414715
94030123854232
101140233214413
113aa62aa18517
12164b99968325
13836a6273c17
143d28aa21a0d
151e9d7ba3528
hex1097b3219cd

1140233214413 has 4 divisors (see below), whose sum is σ = 1140241528608. Its totient is φ = 1140224900220.

The previous prime is 1140233214377. The next prime is 1140233214437. The reversal of 1140233214413 is 3144123320411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1140233214413 - 212 = 1140233210317 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140233214443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3947873 + ... + 4226838.

It is an arithmetic number, because the mean of its divisors is an integer number (285060382152).

Almost surely, 21140233214413 is an apocalyptic number.

It is an amenable number.

1140233214413 is a deficient number, since it is larger than the sum of its proper divisors (8314195).

1140233214413 is an equidigital number, since it uses as much as digits as its factorization.

1140233214413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8314194.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1140233214413 its reverse (3144123320411), we get a palindrome (4284356534824).

The spelling of 1140233214413 in words is "one trillion, one hundred forty billion, two hundred thirty-three million, two hundred fourteen thousand, four hundred thirteen".

Divisors: 1 139483 8174711 1140233214413