Base | Representation |
---|---|
bin | 10000100101111011100… |
… | …110111001111111110010 |
3 | 11001000011021222011201012 |
4 | 100211323212321333302 |
5 | 122140202433130114 |
6 | 2231452531110522 |
7 | 145244133121625 |
oct | 20457346717762 |
9 | 4030137864635 |
10 | 1140240130034 |
11 | 3aa633911305 |
12 | 164ba0142442 |
13 | 836a78258c5 |
14 | 3d28b901dbc |
15 | 1e9d85bc63e |
hex | 1097b9b9ff2 |
1140240130034 has 4 divisors (see below), whose sum is σ = 1710360195054. Its totient is φ = 570120065016.
The previous prime is 1140240130013. The next prime is 1140240130069. The reversal of 1140240130034 is 4300310420411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1036171305625 + 104068824409 = 1017925^2 + 322597^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1140240129991 and 1140240130009.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 285060032507 + ... + 285060032510.
Almost surely, 21140240130034 is an apocalyptic number.
1140240130034 is a deficient number, since it is larger than the sum of its proper divisors (570120065020).
1140240130034 is an equidigital number, since it uses as much as digits as its factorization.
1140240130034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 570120065019.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1140240130034 its reverse (4300310420411), we get a palindrome (5440550550445).
The spelling of 1140240130034 in words is "one trillion, one hundred forty billion, two hundred forty million, one hundred thirty thousand, thirty-four".
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