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1140240130034 = 2570120065017
BaseRepresentation
bin10000100101111011100…
…110111001111111110010
311001000011021222011201012
4100211323212321333302
5122140202433130114
62231452531110522
7145244133121625
oct20457346717762
94030137864635
101140240130034
113aa633911305
12164ba0142442
13836a78258c5
143d28b901dbc
151e9d85bc63e
hex1097b9b9ff2

1140240130034 has 4 divisors (see below), whose sum is σ = 1710360195054. Its totient is φ = 570120065016.

The previous prime is 1140240130013. The next prime is 1140240130069. The reversal of 1140240130034 is 4300310420411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1036171305625 + 104068824409 = 1017925^2 + 322597^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1140240129991 and 1140240130009.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 285060032507 + ... + 285060032510.

Almost surely, 21140240130034 is an apocalyptic number.

1140240130034 is a deficient number, since it is larger than the sum of its proper divisors (570120065020).

1140240130034 is an equidigital number, since it uses as much as digits as its factorization.

1140240130034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 570120065019.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1140240130034 its reverse (4300310420411), we get a palindrome (5440550550445).

The spelling of 1140240130034 in words is "one trillion, one hundred forty billion, two hundred forty million, one hundred thirty thousand, thirty-four".

Divisors: 1 2 570120065017 1140240130034