Base | Representation |
---|---|
bin | 1010010111101101010011… |
… | …1001010111111001001011 |
3 | 1111101001121220111102221212 |
4 | 2211323110321113321023 |
5 | 2443304121220412301 |
6 | 40130110325523335 |
7 | 2254540321311020 |
oct | 245732471277113 |
9 | 44331556442855 |
10 | 11402415013451 |
11 | 36a68120186a0 |
12 | 1341a4587354b |
13 | 6493211a6827 |
14 | 2b5c46385547 |
15 | 14b90a0e24bb |
hex | a5ed4e57e4b |
11402415013451 has 16 divisors (see below), whose sum is σ = 14248380664320. Its totient is φ = 8864759508480.
The previous prime is 11402415013441. The next prime is 11402415013469. The reversal of 11402415013451 is 15431051420411.
It is a cyclic number.
It is not a de Polignac number, because 11402415013451 - 214 = 11402414997067 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11402415013421) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 168626006 + ... + 168693611.
It is an arithmetic number, because the mean of its divisors is an integer number (890523791520).
Almost surely, 211402415013451 is an apocalyptic number.
11402415013451 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11402415013451 is a deficient number, since it is larger than the sum of its proper divisors (2845965650869).
11402415013451 is a wasteful number, since it uses less digits than its factorization.
11402415013451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 337320074.
The product of its (nonzero) digits is 9600, while the sum is 32.
Adding to 11402415013451 its reverse (15431051420411), we get a palindrome (26833466433862).
The spelling of 11402415013451 in words is "eleven trillion, four hundred two billion, four hundred fifteen million, thirteen thousand, four hundred fifty-one".
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