Base | Representation |
---|---|
bin | 11001111011010100111010… |
… | …100100011001101010011101 |
3 | 112221201222101012200211102120 |
4 | 121323110322210121222131 |
5 | 104421213441224043313 |
6 | 1042303434421413153 |
7 | 33006153600256410 |
oct | 3173247244315235 |
9 | 487658335624376 |
10 | 114028069362333 |
11 | 3337303a4a4175 |
12 | 109574a186a1b9 |
13 | 4b81a54492119 |
14 | 2022db9127b77 |
15 | d2b1e9a85d23 |
hex | 67b53a919a9d |
114028069362333 has 16 divisors (see below), whose sum is σ = 173789973012480. Its totient is φ = 65146553677296.
The previous prime is 114028069362329. The next prime is 114028069362349. The reversal of 114028069362333 is 333263960820411.
It is not a de Polignac number, because 114028069362333 - 22 = 114028069362329 is a prime.
It is a super-3 number, since 3×1140280693623333 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114028069352333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 514182385 + ... + 514404102.
It is an arithmetic number, because the mean of its divisors is an integer number (10861873313280).
Almost surely, 2114028069362333 is an apocalyptic number.
It is an amenable number.
114028069362333 is a deficient number, since it is larger than the sum of its proper divisors (59761903650147).
114028069362333 is a wasteful number, since it uses less digits than its factorization.
114028069362333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1028591776.
The product of its (nonzero) digits is 3359232, while the sum is 51.
The spelling of 114028069362333 in words is "one hundred fourteen trillion, twenty-eight billion, sixty-nine million, three hundred sixty-two thousand, three hundred thirty-three".
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