Base | Representation |
---|---|
bin | 1010010111101111101000… |
… | …1111000010100010011111 |
3 | 1111101010020120020201112211 |
4 | 2211323322033002202133 |
5 | 2443311412102401033 |
6 | 40130252424341251 |
7 | 2254561666035040 |
oct | 245737217024237 |
9 | 44333216221484 |
10 | 11403041450143 |
11 | 36a7003692872 |
12 | 1341b9b614827 |
13 | 6493c0bca525 |
14 | 2b5ca56508c7 |
15 | 14b9450d32cd |
hex | a5efa3c289f |
11403041450143 has 16 divisors (see below), whose sum is σ = 13489807464000. Its totient is φ = 9431134417152.
The previous prime is 11403041450117. The next prime is 11403041450183. The reversal of 11403041450143 is 34105414030411.
It is not a de Polignac number, because 11403041450143 - 25 = 11403041450111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11403041450113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17129128 + ... + 17782381.
It is an arithmetic number, because the mean of its divisors is an integer number (843112966500).
Almost surely, 211403041450143 is an apocalyptic number.
11403041450143 is a deficient number, since it is larger than the sum of its proper divisors (2086766013857).
11403041450143 is a wasteful number, since it uses less digits than its factorization.
11403041450143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34913154.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 11403041450143 its reverse (34105414030411), we get a palindrome (45508455480554).
The spelling of 11403041450143 in words is "eleven trillion, four hundred three billion, forty-one million, four hundred fifty thousand, one hundred forty-three".
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