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1140311431143 = 3415881886463
BaseRepresentation
bin10000100101111111110…
…110111001011111100111
311001000100021010122110000
4100211333312321133213
5122140324211244033
62231503555232343
7145245660144603
oct20457766713747
94030307118400
101140311431143
113aa670090945
12164bbbba86b3
13836b952b701
143d297182503
151e9de9a3a13
hex1097fdb97e7

1140311431143 has 20 divisors (see below), whose sum is σ = 1703537371008. Its totient is φ = 760158894240.

The previous prime is 1140311431123. The next prime is 1140311431211. The reversal of 1140311431143 is 3411341130411.

1140311431143 is a `hidden beast` number, since 1 + 1 + 403 + 1 + 143 + 114 + 3 = 666.

It is not a de Polignac number, because 1140311431143 - 29 = 1140311430631 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140311431123) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 843130 + ... + 1729592.

Almost surely, 21140311431143 is an apocalyptic number.

1140311431143 is a deficient number, since it is larger than the sum of its proper divisors (563225939865).

1140311431143 is an equidigital number, since it uses as much as digits as its factorization.

1140311431143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 902356 (or 902347 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 1140311431143 its reverse (3411341130411), we get a palindrome (4551652561554).

The spelling of 1140311431143 in words is "one trillion, one hundred forty billion, three hundred eleven million, four hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 3 9 27 81 15881 47643 142929 428787 886463 1286361 2659389 7978167 23934501 71803503 14077918903 42233756709 126701270127 380103810381 1140311431143