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114032012111 = 148776685953
BaseRepresentation
bin110101000110011010…
…1100110101101001111
3101220100002100102011222
41222030311212231033
53332014143341421
6124215141433555
711144551052543
oct1521465465517
9356302312158
10114032012111
11443a7109526
121a12510b8bb
13a9a39493a4
14573a8aba23
152e76092cab
hex1a8cd66b4f

114032012111 has 4 divisors (see below), whose sum is σ = 114108699552. Its totient is φ = 113955324672.

The previous prime is 114032012099. The next prime is 114032012183. The reversal of 114032012111 is 111210230411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114032012111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114032012111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114032017111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38341490 + ... + 38344463.

It is an arithmetic number, because the mean of its divisors is an integer number (28527174888).

Almost surely, 2114032012111 is an apocalyptic number.

114032012111 is a deficient number, since it is larger than the sum of its proper divisors (76687441).

114032012111 is an equidigital number, since it uses as much as digits as its factorization.

114032012111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76687440.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 114032012111 its reverse (111210230411), we get a palindrome (225242242522).

The spelling of 114032012111 in words is "one hundred fourteen billion, thirty-two million, twelve thousand, one hundred eleven".

Divisors: 1 1487 76685953 114032012111