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11403342115153 = 73156210165961
BaseRepresentation
bin1010010111110000110000…
…1001111111000101010001
31111101011000112000002101221
42211330030021333011101
52443313021040141103
640130342324525041
72254602306454312
oct245741411770521
944334015002357
1011403342115153
1136a714838094a
121342064250781
1364943b29bc11
142b5cd3558609
1514b9616c41bd
hexa5f0c27f151

11403342115153 has 4 divisors (see below), whose sum is σ = 11559552281188. Its totient is φ = 11247131949120.

The previous prime is 11403342115063. The next prime is 11403342115199. The reversal of 11403342115153 is 35151124330411.

11403342115153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9597777488784 + 1805564626369 = 3098028^2 + 1343713^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11403342115153 is a prime.

It is a super-2 number, since 2×114033421151532 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11403342115453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78105082908 + ... + 78105083053.

It is an arithmetic number, because the mean of its divisors is an integer number (2889888070297).

Almost surely, 211403342115153 is an apocalyptic number.

It is an amenable number.

11403342115153 is a deficient number, since it is larger than the sum of its proper divisors (156210166035).

11403342115153 is an equidigital number, since it uses as much as digits as its factorization.

11403342115153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156210166034.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 11403342115153 its reverse (35151124330411), we get a palindrome (46554466445564).

The spelling of 11403342115153 in words is "eleven trillion, four hundred three billion, three hundred forty-two million, one hundred fifteen thousand, one hundred fifty-three".

Divisors: 1 73 156210165961 11403342115153