1140341111233 has 4 divisors (see below), whose sum is σ = 1140370420480. Its totient is φ = 1140311801988.

The previous prime is 1140341111209. The next prime is 1140341111251. The reversal of 1140341111233 is 3321111430411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1140341111233 - 2⁵ = 1140341111201 is a prime.

It is a super-2 number, since 2×1140341111233² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1140341111198 and 1140341111207.

It is not an unprimeable number, because it can be changed into a prime (1140341115233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14596185 + ... + 14674102.

It is an arithmetic number, because the mean of its divisors is an integer number (285092605120).

Almost surely, 2^{1140341111233} is an apocalyptic number.

It is an amenable number.

1140341111233 is a deficient number, since it is larger than the sum of its proper divisors (29309247).

1140341111233 is an equidigital number, since it uses as much as digits as its factorization.

1140341111233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29309246.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1140341111233 its reverse (3321111430411), we get a palindrome (4461452541644).

The spelling of 1140341111233 in words is "one trillion, one hundred forty billion, three hundred forty-one million, one hundred eleven thousand, two hundred thirty-three".