1140342013 has 4 divisors (see below), whose sum is σ = 1140415488. Its totient is φ = 1140268540.

The previous prime is 1140341999. The next prime is 1140342041. The reversal of 1140342013 is 3102430411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3102430411 = 29 ⋅106980359.

It is a cyclic number.

It is not a de Polignac number, because 1140342013 - 2¹⁷ = 1140210941 is a prime.

It is a super-2 number, since 2×1140342013² = 2600759813225784338, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140342043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3331 + ... + 47872.

It is an arithmetic number, because the mean of its divisors is an integer number (285103872).

Almost surely, 2^1140342013 is an apocalyptic number.

It is an amenable number.

1140342013 is a deficient number, since it is larger than the sum of its proper divisors (73475).

1140342013 is an equidigital number, since it uses as much as digits as its factorization.

1140342013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73474.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 1140342013 is about 33768.9504278709. The cubic root of 1140342013 is about 1044.7483847404.

Adding to 1140342013 its reverse (3102430411), we get a palindrome (4242772424).

The spelling of 1140342013 in words is "one billion, one hundred forty million, three hundred forty-two thousand, thirteen".