114041243141131 has 4 divisors (see below), whose sum is σ = 117973699801200. Its totient is φ = 110108786481064.

The previous prime is 114041243141113. The next prime is 114041243141171. The reversal of 114041243141131 is 131141342140411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114041243141131 - 2²⁵ = 114041209586699 is a prime.

It is a super-2 number, since 2×114041243141131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114041243141093 and 114041243141102.

It is not an unprimeable number, because it can be changed into a prime (114041243141171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1966228329991 + ... + 1966228330048.

It is an arithmetic number, because the mean of its divisors is an integer number (29493424950300).

Almost surely, 2^{114041243141131} is an apocalyptic number.

114041243141131 is a deficient number, since it is larger than the sum of its proper divisors (3932456660069).

114041243141131 is an equidigital number, since it uses as much as digits as its factorization.

114041243141131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3932456660068.

The product of its (nonzero) digits is 4608, while the sum is 31.

Adding to 114041243141131 its reverse (131141342140411), we get a palindrome (245182585281542).

The spelling of 114041243141131 in words is "one hundred fourteen trillion, forty-one billion, two hundred forty-three million, one hundred forty-one thousand, one hundred thirty-one".