Base | Representation |
---|---|
bin | 11101110100010110111001… |
… | …000111010001011111111011 |
3 | 122012022222201121121101112011 |
4 | 131310112321013101133323 |
5 | 114142104432041443121 |
6 | 1142525300105030351 |
7 | 36423435465631561 |
oct | 3564267107213773 |
9 | 565288647541464 |
10 | 131141342140411 |
11 | 38870804877209 |
12 | 128600a21853b7 |
13 | 58237634b3825 |
14 | 24553bc1a3a31 |
15 | 10264497977e1 |
hex | 7745b91d17fb |
131141342140411 has 2 divisors, whose sum is σ = 131141342140412. Its totient is φ = 131141342140410.
The previous prime is 131141342140399. The next prime is 131141342140429. The reversal of 131141342140411 is 114041243141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141342140411 - 219 = 131141341616123 is a prime.
It is not a weakly prime, because it can be changed into another prime (131141342140811) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570671070205 + 65570671070206.
It is an arithmetic number, because the mean of its divisors is an integer number (65570671070206).
Almost surely, 2131141342140411 is an apocalyptic number.
131141342140411 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141342140411 is an equidigital number, since it uses as much as digits as its factorization.
131141342140411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 31.
Adding to 131141342140411 its reverse (114041243141131), we get a palindrome (245182585281542).
The spelling of 131141342140411 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-two million, one hundred forty thousand, four hundred eleven".
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