114041250413551 has 4 divisors (see below), whose sum is σ = 117123446370712. Its totient is φ = 110959054456392.

The previous prime is 114041250413491. The next prime is 114041250413557. The reversal of 114041250413551 is 155314052140411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114041250413551 - 2⁴³ = 105245157391343 is a prime.

It is a super-2 number, since 2×114041250413551² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (37), and also a Moran number because the ratio is a prime number: 3082195957123 = 114041250413551 / (1 + 1 + 4 + 0 + 4 + 1 + 2 + 5 + 0 + 4 + 1 + 3 + 5 + 5 + 1).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114041250413551.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114041250413557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1541097978525 + ... + 1541097978598.

It is an arithmetic number, because the mean of its divisors is an integer number (29280861592678).

Almost surely, 2^{114041250413551} is an apocalyptic number.

114041250413551 is a deficient number, since it is larger than the sum of its proper divisors (3082195957161).

114041250413551 is an equidigital number, since it uses as much as digits as its factorization.

114041250413551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3082195957160.

The product of its (nonzero) digits is 48000, while the sum is 37.

The spelling of 114041250413551 in words is "one hundred fourteen trillion, forty-one billion, two hundred fifty million, four hundred thirteen thousand, five hundred fifty-one".