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11404220001 = 33801406667
BaseRepresentation
bin10101001111011111…
…01001011001100001
31002102210001101211120
422213233221121201
5141323440020001
65123344002453
7552415161546
oct124757513141
932383041746
1011404220001
114922426309
122263300429
1310c98b5995
147a2852bcd
1546b2d8236
hex2a7be9661

11404220001 has 4 divisors (see below), whose sum is σ = 15205626672. Its totient is φ = 7602813332.

The previous prime is 11404219999. The next prime is 11404220011. The reversal of 11404220001 is 10002240411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11404220001 - 21 = 11404219999 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11404220011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1900703331 + ... + 1900703336.

It is an arithmetic number, because the mean of its divisors is an integer number (3801406668).

Almost surely, 211404220001 is an apocalyptic number.

It is an amenable number.

11404220001 is a deficient number, since it is larger than the sum of its proper divisors (3801406671).

11404220001 is an equidigital number, since it uses as much as digits as its factorization.

11404220001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3801406670.

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 11404220001 its reverse (10002240411), we get a palindrome (21406460412).

The spelling of 11404220001 in words is "eleven billion, four hundred four million, two hundred twenty thousand, one".

Divisors: 1 3 3801406667 11404220001