114042332113 has 4 divisors (see below), whose sum is σ = 114940303360. Its totient is φ = 113144360868.

The previous prime is 114042332111. The next prime is 114042332123. The reversal of 114042332113 is 311233240411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311233240411 = 107 ⋅2908721873.

It is a cyclic number.

It is not a de Polignac number, because 114042332113 - 2¹ = 114042332111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114042332111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 448985433 + ... + 448985686.

It is an arithmetic number, because the mean of its divisors is an integer number (28735075840).

Almost surely, 2^114042332113 is an apocalyptic number.

It is an amenable number.

114042332113 is a deficient number, since it is larger than the sum of its proper divisors (897971247).

114042332113 is an equidigital number, since it uses as much as digits as its factorization.

114042332113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 897971246.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 114042332113 its reverse (311233240411), we get a palindrome (425275572524).

The spelling of 114042332113 in words is "one hundred fourteen billion, forty-two million, three hundred thirty-two thousand, one hundred thirteen".