114043004515441 has 4 divisors (see below), whose sum is σ = 114227839207332. Its totient is φ = 113858169823552.

The previous prime is 114043004515439. The next prime is 114043004515511. The reversal of 114043004515441 is 144515400340411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 50297471069041 + 63745533446400 = 7092071^2 + 7984080^2 .

It is a cyclic number.

It is not a de Polignac number, because 114043004515441 - 2¹ = 114043004515439 is a prime.

It is a super-3 number, since 3×114043004515441³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114043004515441.

It is not an unprimeable number, because it can be changed into a prime (114043004519441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92417345020 + ... + 92417346253.

It is an arithmetic number, because the mean of its divisors is an integer number (28556959801833).

Almost surely, 2^{114043004515441} is an apocalyptic number.

It is an amenable number.

114043004515441 is a deficient number, since it is larger than the sum of its proper divisors (184834691891).

114043004515441 is an equidigital number, since it uses as much as digits as its factorization.

114043004515441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 184834691890.

The product of its (nonzero) digits is 76800, while the sum is 37.

Adding to 114043004515441 its reverse (144515400340411), we get a palindrome (258558404855852).

The spelling of 114043004515441 in words is "one hundred fourteen trillion, forty-three billion, four million, five hundred fifteen thousand, four hundred forty-one".