Base | Representation |
---|---|
bin | 11001111011100010110100… |
… | …110001011111010001110010 |
3 | 112221210101221001211012220102 |
4 | 121323202310301133101302 |
5 | 104421440033123443232 |
6 | 1042314344421512402 |
7 | 33010222652054012 |
oct | 3173426461372162 |
9 | 487711831735812 |
10 | 114043004515442 |
11 | 33379403a54812 |
12 | 1095a36b572702 |
13 | 4b83294755022 |
14 | 20239d48abc42 |
15 | d2b7c0d3b662 |
hex | 67b8b4c5f472 |
114043004515442 has 4 divisors (see below), whose sum is σ = 171064506773166. Its totient is φ = 57021502257720.
The previous prime is 114043004515439. The next prime is 114043004515511. The reversal of 114043004515442 is 244515400340411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 84109423712161 + 29933580803281 = 9171119^2 + 5471159^2 .
It is a junction number, because it is equal to n+sod(n) for n = 114043004515396 and 114043004515405.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28510751128859 + ... + 28510751128862.
Almost surely, 2114043004515442 is an apocalyptic number.
114043004515442 is a deficient number, since it is larger than the sum of its proper divisors (57021502257724).
114043004515442 is an equidigital number, since it uses as much as digits as its factorization.
114043004515442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57021502257723.
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 114043004515442 its reverse (244515400340411), we get a palindrome (358558404855853).
The spelling of 114043004515442 in words is "one hundred fourteen trillion, forty-three billion, four million, five hundred fifteen thousand, four hundred forty-two".
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