Base | Representation |
---|---|
bin | 11001111011100011010011… |
… | …100100001110011110100101 |
3 | 112221210110021001221002012210 |
4 | 121323203103210032132211 |
5 | 104421442112402214303 |
6 | 1042314511554434033 |
7 | 33010241524200033 |
oct | 3173432344163645 |
9 | 487713231832183 |
10 | 114043521132453 |
11 | 33379649630820 |
12 | 1095a494592919 |
13 | 4b833477a7773 |
14 | 2023a4334b553 |
15 | d2b801388203 |
hex | 67b8d390e7a5 |
114043521132453 has 8 divisors (see below), whose sum is σ = 165881485283616. Its totient is φ = 69117285534800.
The previous prime is 114043521132397. The next prime is 114043521132487. The reversal of 114043521132453 is 354231125340411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114043521132453 - 217 = 114043521001381 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114043521132053) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1727932138338 + ... + 1727932138403.
It is an arithmetic number, because the mean of its divisors is an integer number (20735185660452).
Almost surely, 2114043521132453 is an apocalyptic number.
It is an amenable number.
114043521132453 is a deficient number, since it is larger than the sum of its proper divisors (51837964151163).
114043521132453 is a wasteful number, since it uses less digits than its factorization.
114043521132453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3455864276755.
The product of its (nonzero) digits is 172800, while the sum is 39.
Adding to 114043521132453 its reverse (354231125340411), we get a palindrome (468274646472864).
The spelling of 114043521132453 in words is "one hundred fourteen trillion, forty-three billion, five hundred twenty-one million, one hundred thirty-two thousand, four hundred fifty-three".
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