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11404411081 = 73567145673
BaseRepresentation
bin10101001111100000…
…11000000011001001
31002102210102002221121
422213300120003021
5141324012123311
65123352035241
7552416615620
oct124760300311
932383362847
1011404411081
114922546928
122263392b21
1310c995194b
147a28a26b7
1546b324b71
hex2a7c180c9

11404411081 has 8 divisors (see below), whose sum is σ = 13034263424. Its totient is φ = 9774721440.

The previous prime is 11404411079. The next prime is 11404411093. The reversal of 11404411081 is 18011440411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11404411081 - 21 = 11404411079 is a prime.

It is a super-3 number, since 3×114044110813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (11404411001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 226861 + ... + 272533.

It is an arithmetic number, because the mean of its divisors is an integer number (1629282928).

Almost surely, 211404411081 is an apocalyptic number.

It is an amenable number.

11404411081 is a deficient number, since it is larger than the sum of its proper divisors (1629852343).

11404411081 is an equidigital number, since it uses as much as digits as its factorization.

11404411081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81351.

The product of its (nonzero) digits is 512, while the sum is 25.

Adding to 11404411081 its reverse (18011440411), we get a palindrome (29415851492).

The spelling of 11404411081 in words is "eleven billion, four hundred four million, four hundred eleven thousand, eighty-one".

Divisors: 1 7 35671 45673 249697 319711 1629201583 11404411081