Base | Representation |
---|---|
bin | 110101000110110100… |
… | …0000100111110111001 |
3 | 101220101000020121222210 |
4 | 1222031220010332321 |
5 | 3332031040241241 |
6 | 124220333205333 |
7 | 11145101400522 |
oct | 1521550047671 |
9 | 356330217883 |
10 | 114045243321 |
11 | 44403626309 |
12 | 1a129630849 |
13 | a9a65cc8c9 |
14 | 573c553849 |
15 | 2e77308316 |
hex | 1a8da04fb9 |
114045243321 has 4 divisors (see below), whose sum is σ = 152060324432. Its totient is φ = 76030162212.
The previous prime is 114045243317. The next prime is 114045243329. The reversal of 114045243321 is 123342540411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 114045243321 - 22 = 114045243317 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114045243329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19007540551 + ... + 19007540556.
It is an arithmetic number, because the mean of its divisors is an integer number (38015081108).
Almost surely, 2114045243321 is an apocalyptic number.
It is an amenable number.
114045243321 is a deficient number, since it is larger than the sum of its proper divisors (38015081111).
114045243321 is an equidigital number, since it uses as much as digits as its factorization.
114045243321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38015081110.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 114045243321 its reverse (123342540411), we get a palindrome (237387783732).
The spelling of 114045243321 in words is "one hundred fourteen billion, forty-five million, two hundred forty-three thousand, three hundred twenty-one".
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