Base | Representation |
---|---|
bin | 1010010111110101100100… |
… | …0011010100011111111111 |
3 | 1111101021100102112212122022 |
4 | 2211331121003110133333 |
5 | 2443323141321313003 |
6 | 40131114332110355 |
7 | 2254646263225064 |
oct | 245753103243777 |
9 | 44337312485568 |
10 | 11404632213503 |
11 | 36a774a625931 |
12 | 13423643053bb |
13 | 6495b564b019 |
14 | 2b5db6a1cc6b |
15 | 14b9d9aaa738 |
hex | a5f590d47ff |
11404632213503 has 4 divisors (see below), whose sum is σ = 11404669487760. Its totient is φ = 11404594939248.
The previous prime is 11404632213473. The next prime is 11404632213511. The reversal of 11404632213503 is 30531223640411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11404632213503 - 26 = 11404632213439 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11404632213593) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18174350 + ... + 18791387.
It is an arithmetic number, because the mean of its divisors is an integer number (2851167371940).
Almost surely, 211404632213503 is an apocalyptic number.
11404632213503 is a deficient number, since it is larger than the sum of its proper divisors (37274257).
11404632213503 is an equidigital number, since it uses as much as digits as its factorization.
11404632213503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37274256.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 11404632213503 its reverse (30531223640411), we get a palindrome (41935855853914).
The spelling of 11404632213503 in words is "eleven trillion, four hundred four billion, six hundred thirty-two million, two hundred thirteen thousand, five hundred three".
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