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114052112000035 = 5113359617348843
BaseRepresentation
bin11001111011101011010011…
…100111110010010000100011
3112221211021102210011101001121
4121323223103213302100203
5104422112211133000120
61042322452242513111
733010664441312146
oct3173532347622043
9487737383141047
10114052112000035
1133382257989790
1210960091665797
134b840b6569771
14202421a2a205d
15d2bb5569a5aa
hex67bad39f2423

114052112000035 has 16 divisors (see below), whose sum is σ = 149349032340480. Its totient is φ = 82922296457440.

The previous prime is 114052112000027. The next prime is 114052112000051. The reversal of 114052112000035 is 530000211250411.

It is not a de Polignac number, because 114052112000035 - 23 = 114052112000027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114052111999973 and 114052112000009.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 308489677 + ... + 308859166.

It is an arithmetic number, because the mean of its divisors is an integer number (9334314521280).

Almost surely, 2114052112000035 is an apocalyptic number.

114052112000035 is a deficient number, since it is larger than the sum of its proper divisors (35296920340445).

114052112000035 is a wasteful number, since it uses less digits than its factorization.

114052112000035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 617352218.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 114052112000035 its reverse (530000211250411), we get a palindrome (644052323250446).

The spelling of 114052112000035 in words is "one hundred fourteen trillion, fifty-two billion, one hundred twelve million, thirty-five", and thus it is an aban number.

Divisors: 1 5 11 55 3359 16795 36949 184745 617348843 3086744215 6790837273 33954186365 2073674763637 10368373818185 22810422400007 114052112000035