Base | Representation |
---|---|
bin | 10101001111100110… |
… | …11110111000111101 |
3 | 1002102211221111011111 |
4 | 22213303132320331 |
5 | 141324214204113 |
6 | 5123421322021 |
7 | 552426550252 |
oct | 124763367075 |
9 | 32384844144 |
10 | 11405225533 |
11 | 4922a52829 |
12 | 2263706311 |
13 | 10c9b78580 |
14 | 7a2a35429 |
15 | 46b43613d |
hex | 2a7cdee3d |
11405225533 has 16 divisors (see below), whose sum is σ = 12848048640. Its totient is φ = 10045436544.
The previous prime is 11405225521. The next prime is 11405225563. The reversal of 11405225533 is 33552250411.
It is not a de Polignac number, because 11405225533 - 29 = 11405225021 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11405225495 and 11405225504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11405225563) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 75660 + ... + 168922.
It is an arithmetic number, because the mean of its divisors is an integer number (803003040).
Almost surely, 211405225533 is an apocalyptic number.
11405225533 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11405225533 is a deficient number, since it is larger than the sum of its proper divisors (1442823107).
11405225533 is a wasteful number, since it uses less digits than its factorization.
11405225533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93708.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 11405225533 its reverse (33552250411), we get a palindrome (44957475944).
The spelling of 11405225533 in words is "eleven billion, four hundred five million, two hundred twenty-five thousand, five hundred thirty-three".
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