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1141002303103 = 1387769407931
BaseRepresentation
bin10000100110101001000…
…010010111011001111111
311001002010102010120121101
4100212221002113121333
5122143233042144403
62232100315113531
7145302046360555
oct20465102273177
94032112116541
101141002303103
113aa995066203
121651734428a7
13837996c30a0
143d320c21bd5
151ea3047171d
hex109a909767f

1141002303103 has 4 divisors (see below), whose sum is σ = 1228771711048. Its totient is φ = 1053232895160.

The previous prime is 1141002303097. The next prime is 1141002303113. The reversal of 1141002303103 is 3013032001411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1141002303103 - 221 = 1141000205951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1141002303113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43884703953 + ... + 43884703978.

It is an arithmetic number, because the mean of its divisors is an integer number (307192927762).

Almost surely, 21141002303103 is an apocalyptic number.

1141002303103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1141002303103 is a deficient number, since it is larger than the sum of its proper divisors (87769407945).

1141002303103 is an equidigital number, since it uses as much as digits as its factorization.

1141002303103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87769407944.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1141002303103 its reverse (3013032001411), we get a palindrome (4154034304514).

The spelling of 1141002303103 in words is "one trillion, one hundred forty-one billion, two million, three hundred three thousand, one hundred three".

Divisors: 1 13 87769407931 1141002303103