114101002554451 has 16 divisors (see below), whose sum is σ = 124522614833760. Its totient is φ = 103687525198080.

The previous prime is 114101002554403. The next prime is 114101002554523. The reversal of 114101002554451 is 154455200101411.

It is a cyclic number.

It is not a de Polignac number, because 114101002554451 - 2¹¹ = 114101002552403 is a prime.

It is a super-2 number, since 2×114101002554451² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (114101002554401) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1370228245 + ... + 1370311513.

It is an arithmetic number, because the mean of its divisors is an integer number (7782663427110).

Almost surely, 2^{114101002554451} is an apocalyptic number.

114101002554451 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

114101002554451 is a deficient number, since it is larger than the sum of its proper divisors (10421612279309).

114101002554451 is a wasteful number, since it uses less digits than its factorization.

114101002554451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130614.

The product of its (nonzero) digits is 16000, while the sum is 34.

Adding to 114101002554451 its reverse (154455200101411), we get a palindrome (268556202655862).

The spelling of 114101002554451 in words is "one hundred fourteen trillion, one hundred one billion, two million, five hundred fifty-four thousand, four hundred fifty-one".