114102400020013 has 4 divisors (see below), whose sum is σ = 114103033831260. Its totient is φ = 114101766208768.

The previous prime is 114102400019947. The next prime is 114102400020023. The reversal of 114102400020013 is 310020004201411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9728429235849 + 104373970784164 = 3119043^2 + 10216358^2 .

It is a cyclic number.

It is not a de Polignac number, because 114102400020013 - 2²⁹ = 114101863149101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114102400020023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316635508 + ... + 316995661.

It is an arithmetic number, because the mean of its divisors is an integer number (28525758457815).

Almost surely, 2^{114102400020013} is an apocalyptic number.

It is an amenable number.

114102400020013 is a deficient number, since it is larger than the sum of its proper divisors (633811247).

114102400020013 is an equidigital number, since it uses as much as digits as its factorization.

114102400020013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 633811246.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 114102400020013 its reverse (310020004201411), we get a palindrome (424122404221424).

The spelling of 114102400020013 in words is "one hundred fourteen trillion, one hundred two billion, four hundred million, twenty thousand, thirteen".