114102411250501 has 4 divisors (see below), whose sum is σ = 114546389504652. Its totient is φ = 113658432996352.

The previous prime is 114102411250309. The next prime is 114102411250511. The reversal of 114102411250501 is 105052114201411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 97309839930625 + 16792571319876 = 9864575^2 + 4097874^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114102411250501 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 114102411250501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114102411250511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221989126690 + ... + 221989127203.

It is an arithmetic number, because the mean of its divisors is an integer number (28636597376163).

Almost surely, 2^{114102411250501} is an apocalyptic number.

It is an amenable number.

114102411250501 is a deficient number, since it is larger than the sum of its proper divisors (443978254151).

114102411250501 is an equidigital number, since it uses as much as digits as its factorization.

114102411250501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 443978254150.

The product of its (nonzero) digits is 1600, while the sum is 28.

Adding to 114102411250501 its reverse (105052114201411), we get a palindrome (219154525451912).

The spelling of 114102411250501 in words is "one hundred fourteen trillion, one hundred two billion, four hundred eleven million, two hundred fifty thousand, five hundred one".