114104031421 has 4 divisors (see below), whose sum is σ = 114135356512. Its totient is φ = 114072706332.

The previous prime is 114104031407. The next prime is 114104031449. The reversal of 114104031421 is 124130401411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114104031421 - 2¹⁵ = 114103998653 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114104031392 and 114104031401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114104031521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15657081 + ... + 15664366.

It is an arithmetic number, because the mean of its divisors is an integer number (28533839128).

Almost surely, 2^114104031421 is an apocalyptic number.

It is an amenable number.

114104031421 is a deficient number, since it is larger than the sum of its proper divisors (31325091).

114104031421 is an equidigital number, since it uses as much as digits as its factorization.

114104031421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31325090.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 114104031421 its reverse (124130401411), we get a palindrome (238234432832).

The spelling of 114104031421 in words is "one hundred fourteen billion, one hundred four million, thirty-one thousand, four hundred twenty-one".