Base | Representation |
---|---|
bin | 11001111100100011011101… |
… | …001100110111000010000011 |
3 | 112222001001001111220201010212 |
4 | 121330203131030313002003 |
5 | 104424104144434143003 |
6 | 1042410303000144335 |
7 | 33015230464114154 |
oct | 3174433514670203 |
9 | 488031044821125 |
10 | 114112402256003 |
11 | 333a5886195408 |
12 | 1096b8b87680ab |
13 | 4b899a4192538 |
14 | 20270d950d92b |
15 | d2d4d3634dd8 |
hex | 67c8dd337083 |
114112402256003 has 4 divisors (see below), whose sum is σ = 114169544172000. Its totient is φ = 114055260340008.
The previous prime is 114112402255979. The next prime is 114112402256059. The reversal of 114112402256003 is 300652204211411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114112402256003 - 212 = 114112402251907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114112402256063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28570955003 + ... + 28570958996.
It is an arithmetic number, because the mean of its divisors is an integer number (28542386043000).
Almost surely, 2114112402256003 is an apocalyptic number.
114112402256003 is a deficient number, since it is larger than the sum of its proper divisors (57141915997).
114112402256003 is an equidigital number, since it uses as much as digits as its factorization.
114112402256003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57141915996.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 114112402256003 its reverse (300652204211411), we get a palindrome (414764606467414).
The spelling of 114112402256003 in words is "one hundred fourteen trillion, one hundred twelve billion, four hundred two million, two hundred fifty-six thousand, three".
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