114112433333 has 4 divisors (see below), whose sum is σ = 114114206220. Its totient is φ = 114110660448.

The previous prime is 114112433291. The next prime is 114112433363. The reversal of 114112433333 is 333334211411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 92938400164 + 21174033169 = 304858^2 + 145513^2 .

It is a cyclic number.

It is not a de Polignac number, because 114112433333 - 2¹⁰ = 114112432309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114112433296 and 114112433305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114112433363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786110 + ... + 919887.

It is an arithmetic number, because the mean of its divisors is an integer number (28528551555).

Almost surely, 2^114112433333 is an apocalyptic number.

It is an amenable number.

114112433333 is a deficient number, since it is larger than the sum of its proper divisors (1772887).

114112433333 is an equidigital number, since it uses as much as digits as its factorization.

114112433333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1772886.

The product of its digits is 7776, while the sum is 29.

Adding to 114112433333 its reverse (333334211411), we get a palindrome (447446644744).

The spelling of 114112433333 in words is "one hundred fourteen billion, one hundred twelve million, four hundred thirty-three thousand, three hundred thirty-three".