11411323434433 has 8 divisors (see below), whose sum is σ = 12289692558528. Its totient is φ = 10533036455184.

The previous prime is 11411323434431. The next prime is 11411323434439. The reversal of 11411323434433 is 33443432311411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11411323434433 - 2¹ = 11411323434431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11411323434392 and 11411323434401.

It is not an unprimeable number, because it can be changed into a prime (11411323434431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20247535 + ... + 20803492.

It is an arithmetic number, because the mean of its divisors is an integer number (1536211569816).

Almost surely, 2^{11411323434433} is an apocalyptic number.

11411323434433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11411323434433 is a deficient number, since it is larger than the sum of its proper divisors (878369124095).

11411323434433 is a wasteful number, since it uses less digits than its factorization.

11411323434433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41072423.

The product of its digits is 124416, while the sum is 37.

Adding to 11411323434433 its reverse (33443432311411), we get a palindrome (44854755745844).

The spelling of 11411323434433 in words is "eleven trillion, four hundred eleven billion, three hundred twenty-three million, four hundred thirty-four thousand, four hundred thirty-three".