Base | Representation |
---|---|
bin | 1010011000001110011111… |
… | …1000010011010111000111 |
3 | 1111101220121202021010011221 |
4 | 2212003213320103113013 |
5 | 2443430342244400224 |
6 | 40134142320141211 |
7 | 2255304142531615 |
oct | 246034770232707 |
9 | 44356552233157 |
10 | 11411323434439 |
11 | 36aa57364a195 |
12 | 1343711167807 |
13 | 64a1109a1256 |
14 | 2b644d55c6b5 |
15 | 14bc7c22e6e4 |
hex | a60e7e135c7 |
11411323434439 has 2 divisors, whose sum is σ = 11411323434440. Its totient is φ = 11411323434438.
The previous prime is 11411323434431. The next prime is 11411323434463. The reversal of 11411323434439 is 93443432311411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11411323434439 - 23 = 11411323434431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11411323434395 and 11411323434404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11411323434431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705661717219 + 5705661717220.
It is an arithmetic number, because the mean of its divisors is an integer number (5705661717220).
Almost surely, 211411323434439 is an apocalyptic number.
11411323434439 is a deficient number, since it is larger than the sum of its proper divisors (1).
11411323434439 is an equidigital number, since it uses as much as digits as its factorization.
11411323434439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 373248, while the sum is 43.
The spelling of 11411323434439 in words is "eleven trillion, four hundred eleven billion, three hundred twenty-three million, four hundred thirty-four thousand, four hundred thirty-nine".
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