Base | Representation |
---|---|
bin | 10101010000010101… |
… | …10001011010001101 |
3 | 1002110021102122212211 |
4 | 22220022301122031 |
5 | 141332300040301 |
6 | 5124200230421 |
7 | 552532465501 |
oct | 125012613215 |
9 | 32407378784 |
10 | 11411330701 |
11 | 4926442721 |
12 | 226576b411 |
13 | 10cb2053b4 |
14 | 7a3784301 |
15 | 46bc40051 |
hex | 2a82b168d |
11411330701 has 4 divisors (see below), whose sum is σ = 11411646652. Its totient is φ = 11411014752.
The previous prime is 11411330647. The next prime is 11411330741. The reversal of 11411330701 is 10703311411.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10703311411 = 13 ⋅823331647.
It can be written as a sum of positive squares in 2 ways, for example, as 7106658601 + 4304672100 = 84301^2 + 65610^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11411330701 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11411330741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95586 + ... + 178771.
It is an arithmetic number, because the mean of its divisors is an integer number (2852911663).
Almost surely, 211411330701 is an apocalyptic number.
It is an amenable number.
11411330701 is a deficient number, since it is larger than the sum of its proper divisors (315951).
11411330701 is an equidigital number, since it uses as much as digits as its factorization.
11411330701 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 315950.
The product of its (nonzero) digits is 252, while the sum is 22.
The spelling of 11411330701 in words is "eleven billion, four hundred eleven million, three hundred thirty thousand, seven hundred one".
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