Base | Representation |
---|---|
bin | 1010011000001110100010… |
… | …0010010011011111010111 |
3 | 1111101220122111222111212001 |
4 | 2212003220202103133113 |
5 | 2443430403104220030 |
6 | 40134143352140131 |
7 | 2255304335240461 |
oct | 246035042233727 |
9 | 44356574874761 |
10 | 11411334445015 |
11 | 36aa57988a63a |
12 | 1343714997647 |
13 | 64a113057a9b |
14 | 2b6450bc7131 |
15 | 14bc7d1a6cca |
hex | a60e88937d7 |
11411334445015 has 8 divisors (see below), whose sum is σ = 13695775304400. Its totient is φ = 9127618242432.
The previous prime is 11411334444997. The next prime is 11411334445031. The reversal of 11411334445015 is 51054443311411.
11411334445015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11411334445015 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 181129554 + ... + 181192543.
It is an arithmetic number, because the mean of its divisors is an integer number (1711971913050).
Almost surely, 211411334445015 is an apocalyptic number.
11411334445015 is a deficient number, since it is larger than the sum of its proper divisors (2284440859385).
11411334445015 is an equidigital number, since it uses as much as digits as its factorization.
11411334445015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 362328401.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 11411334445015 its reverse (51054443311411), we get a palindrome (62465777756426).
The spelling of 11411334445015 in words is "eleven trillion, four hundred eleven billion, three hundred thirty-four million, four hundred forty-five thousand, fifteen".
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