Base | Representation |
---|---|
bin | 11001111100100101010101… |
… | …100101101001100000100011 |
3 | 112222001020021021110100122200 |
4 | 121330211111211221200203 |
5 | 104424122314014121011 |
6 | 1042411235230504243 |
7 | 33015331520613261 |
oct | 3174452545514043 |
9 | 488036237410580 |
10 | 114114422020131 |
11 | 333a6722301065 |
12 | 10970181065083 |
13 | 4b89c36769840 |
14 | 202724b871431 |
15 | d2d5a0aed856 |
hex | 67c955969823 |
114114422020131 has 24 divisors (see below), whose sum is σ = 177655758942480. Its totient is φ = 70167120267456.
The previous prime is 114114422020063. The next prime is 114114422020141. The reversal of 114114422020131 is 131020224411411.
114114422020131 is a `hidden beast` number, since 1 + 1 + 4 + 1 + 1 + 4 + 422 + 0 + 201 + 31 = 666.
It is not a de Polignac number, because 114114422020131 - 237 = 113976983066659 is a prime.
It is a super-2 number, since 2×1141144220201312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114114422020095 and 114114422020104.
It is not an unprimeable number, because it can be changed into a prime (114114422020141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 396657241 + ... + 396944826.
It is an arithmetic number, because the mean of its divisors is an integer number (7402323289270).
Almost surely, 2114114422020131 is an apocalyptic number.
114114422020131 is a deficient number, since it is larger than the sum of its proper divisors (63541336922349).
114114422020131 is a wasteful number, since it uses less digits than its factorization.
114114422020131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 793603315 (or 793603312 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 27.
Adding to 114114422020131 its reverse (131020224411411), we get a palindrome (245134646431542).
The spelling of 114114422020131 in words is "one hundred fourteen trillion, one hundred fourteen billion, four hundred twenty-two million, twenty thousand, one hundred thirty-one".
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