1141144411303 has 4 divisors (see below), whose sum is σ = 1228924750648. Its totient is φ = 1053364071960.

The previous prime is 1141144411243. The next prime is 1141144411343. The reversal of 1141144411303 is 3031144411411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1141144411303 - 2¹³ = 1141144403111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1141144411343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43890169653 + ... + 43890169678.

It is an arithmetic number, because the mean of its divisors is an integer number (307231187662).

Almost surely, 2^{1141144411303} is an apocalyptic number.

1141144411303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1141144411303 is a deficient number, since it is larger than the sum of its proper divisors (87780339345).

1141144411303 is an equidigital number, since it uses as much as digits as its factorization.

1141144411303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87780339344.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 1141144411303 its reverse (3031144411411), we get a palindrome (4172288822714).

The spelling of 1141144411303 in words is "one trillion, one hundred forty-one billion, one hundred forty-four million, four hundred eleven thousand, three hundred three".