114120113 has 4 divisors (see below), whose sum is σ = 114485028. Its totient is φ = 113755200.

The previous prime is 114120107. The next prime is 114120119. The reversal of 114120113 is 311021411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311021411 = 2411 ⋅129001.

It is an interprime number because it is at equal distance from previous prime (114120107) and next prime (114120119).

It can be written as a sum of positive squares in 2 ways, for example, as 5793649 + 108326464 = 2407^2 + 10408^2 .

It is a cyclic number.

It is not a de Polignac number, because 114120113 - 2⁸ = 114119857 is a prime.

It is a super-2 number, since 2×114120113² = 26046800382265538, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (114120119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181988 + ... + 182613.

It is an arithmetic number, because the mean of its divisors is an integer number (28621257).

Almost surely, 2^114120113 is an apocalyptic number.

It is an amenable number.

114120113 is a deficient number, since it is larger than the sum of its proper divisors (364915).

114120113 is an equidigital number, since it uses as much as digits as its factorization.

114120113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 364914.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 114120113 is about 10682.7015777845. The cubic root of 114120113 is about 485.0509926191.

Adding to 114120113 its reverse (311021411), we get a palindrome (425141524).

The spelling of 114120113 in words is "one hundred fourteen million, one hundred twenty thousand, one hundred thirteen".