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1141210314403 = 2956591695377
BaseRepresentation
bin10000100110110101011…
…011110111011010100011
311001002122220112122110121
4100212311123313122203
5122144144320030103
62232133105341111
7145310153422525
oct20466533673243
94032586478417
101141210314403
113aaa91520175
12165211037797
13838008239b3
143d3406cba15
151ea4385e6bd
hex109b56f76a3

1141210314403 has 8 divisors (see below), whose sum is σ = 1180584953280. Its totient is φ = 1101837179520.

The previous prime is 1141210314397. The next prime is 1141210314479. The reversal of 1141210314403 is 3044130121411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1141210314403 - 221 = 1141208217251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1141210384403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1293451 + ... + 1988827.

It is an arithmetic number, because the mean of its divisors is an integer number (147573119160).

Almost surely, 21141210314403 is an apocalyptic number.

1141210314403 is a deficient number, since it is larger than the sum of its proper divisors (39374638877).

1141210314403 is an equidigital number, since it uses as much as digits as its factorization.

1141210314403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 751997.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1141210314403 its reverse (3044130121411), we get a palindrome (4185340435814).

The spelling of 1141210314403 in words is "one trillion, one hundred forty-one billion, two hundred ten million, three hundred fourteen thousand, four hundred three".

Divisors: 1 29 56591 695377 1641139 20165933 39352079807 1141210314403