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11412330213 = 33804110071
BaseRepresentation
bin10101010000011101…
…00101011011100101
31002110100022102221210
422220032211123211
5141333024031323
65124233502033
7552544130514
oct125016453345
932410272853
1011412330213
114926a65669
122265b71919
1310cb49531b
147a396467b
1546bd8b293
hex2a83a56e5

11412330213 has 4 divisors (see below), whose sum is σ = 15216440288. Its totient is φ = 7608220140.

The previous prime is 11412330199. The next prime is 11412330227. The reversal of 11412330213 is 31203321411.

11412330213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (11412330199) and next prime (11412330227).

It is not a de Polignac number, because 11412330213 - 29 = 11412329701 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11412330213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11412330253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1902055033 + ... + 1902055038.

It is an arithmetic number, because the mean of its divisors is an integer number (3804110072).

Almost surely, 211412330213 is an apocalyptic number.

It is an amenable number.

11412330213 is a deficient number, since it is larger than the sum of its proper divisors (3804110075).

11412330213 is an equidigital number, since it uses as much as digits as its factorization.

11412330213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3804110074.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11412330213 its reverse (31203321411), we get a palindrome (42615651624).

The spelling of 11412330213 in words is "eleven billion, four hundred twelve million, three hundred thirty thousand, two hundred thirteen".

Divisors: 1 3 3804110071 11412330213